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Zirconium has two allotropes: body-centered cubic (bcc) zirconium and hexagonal close-packed (hcp). The driving force for the transformation of bcc Zr to hcp Zr is:

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Zirconium has two allotropes: body-centered cubic (bcc) zirconium and hexagonal close-packed (hcp). The driving force for the transformation of bcc Zr to hcp Zr is: DG=3.433DTJ/mol Using this information, calculate the driving force for the transformation Zr(bcc)Zr(hcp) at temperatures of 1130K, 1120K and 1110K. Can you answer these seemingly simple questions? If not, what questions could you answer using this expression, and does it seem that the questions you can answer are useful? Also if not, what other information, at a minimum, would you need to answer the original questions

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