Zn2 + reacts with a biomolecule, B, in solutions at two different pH and at several different salinities (NaCl).

Determine the charge of the biomolecule and k0 "k0 is the rate constant at infinite dilution", (second order) , at the two different pH values

(assume that Zn2 + does not change the state of charge and has the same hydration regardless of pH)

The pH is adjusted with HCl

[ZnCl2] initial = 1.00 mM

pH = 3.0 or 5.0

[B] initial= 1.40 x 10 -6 M

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I think it might be useful if you use the relations:

log k = log k0 + ZaZb

Where I is the ionic strength to the ions: Zn+2 , B, Cl- , H+ , Na +

			[B] M
pH=3	time (min)	[NaCl] mM	50	75	100	150	200
	1		1.39E-06	1.38E-06	1.37E-06	1.33E-06	1.29E-06
	2		1.37E-06	1.35E-06	1.33E-06	1.27E-06	1.18E-06
	3		1.36E-06	1.33E-06	1.30E-06	1.21E-06	1.09E-06
	4		1.34E-06	1.31E-06	1.27E-06	1.16E-06	1.00E-06
	5		1.33E-06	1.29E-06	1.24E-06	1.10E-06	9.22E-07
			[B] M
pH=5	time (min)	[NaCl] mM	50	75	100	150	200
	1		1.34E-06	1.36E-06	1.36E-06	1.37E-06	1.38E-06
	2		1.29E-06	1.31E-06	1.33E-06	1.35E-06	1.36E-06
	3		1.24E-06	1.27E-06	1.29E-06	1.32E-06	1.34E-06
	4		1.19E-06	1.23E-06	1.26E-06	1.30E-06	1.32E-06
	5		1.14E-06	1.19E-06	1.23E-06	1.27E-06	1.30E-06