Measurements on a practical inductor at 10 MHz give L = 8.0 H and Q ind =

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Measurements on a practical inductor at 10 MHz give L = 8.0 µH and Q_ind = 40.

(a) Find the ideal capacitance C for parallel resonance at 10 MHz and calculate the corresponding bandwidth β.

(b) Repeat, if a practical capacitor, with a dissipation factor D = Q⁻¹_ca_p= 0.005 at 10 MHz, is used instead of an ideal capacitance

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Schaum S Outline Of Electric Circuits

ISBN: 9781260011968

7th Edition

Authors: Mahmood Nahvi, Joseph Edminister

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Question Posted: Dec 17, 2023 05:24 AM

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Measurements on a practical inductor at 10 MHz give L = 8.0 H and Q ind =

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Step by Step Answer:

a To find the ideal capacitance C for parallel resonance at 10 MHz we can use the formula C 1 42f2L ...View the full answer

Schaum S Outline Of Electric Circuits

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