In Example 19.10, a laboratory test was conducted with a small, tubular-bowl centrifuge on a fermentation broth.

Question:

In Example 19.10, a laboratory test was conducted with a small, tubular-bowl centrifuge on a fermentation broth. At the operating conditions, a sigma value of 7,400 ftwas computed, with a measured volumetric flow rate of 0.11 gpm. For the commercial plant that will process the same broth, the largest tubular bowl centrifuge available has the following characteristics: bowl speed = 15,000 rpm, R= 5 cm, R= 2 cm, and bowl length = L = 10 cm. Using the sigma scale-up theory, calculate how many gpm this unit can process.


Example 19.10

A laboratory tubular-bowl centrifuge has the following dimensions, with respect to Figure 19.28, and operating conditions: bowl speed 800 rps, R=  0.875 inch, R= 0.65 in., and bowl length = L = 4.5 inches. When used to remove E. coli cells from the following fermentation broth, a satisfactory volumetric feed capacity of the centrifuge, Q, of 0.11 gpm is achieved.

Broth: ρ= 1.01 g/cm3 and μ = 1.02x10–3 kg/m-s

E. coli: smallest diameter = dpmin = 0.7 μm and ρp = 1.04 g/cm3

Assuming the applicability of Stokes’ law, estimate the feed capacity of the centrifuge.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Separation Process Principles Chemical And Biochemical Principles

ISBN: 9780470481837

3rd Edition

Authors: By J. D. Seader, Ernest J. Henley, D. Keith Roper

Question Posted: