Question: Suppose we cascade a differentiator and a smoother. The equations for the differentiator is w[n] = x[n] x[n 1] where w[n] is the output and

Suppose we cascade a differentiator and a smoother. The equations for the differentiator is w[n] = x[n] ˆ’ x[n ˆ’ 1] where w[n] is the output and x[n] the input, and for the smoother the equation is

y[n] = {y[n – 1]+ w[n]

where y[n] is the output and w[n] the input.

(a) Obtain the difference equation relating the input x[n] to the output y[n] of the whole system.

(b) If x[n] = u[n], calculate y[n]. Assume zero initial conditions.

(c) Determine the steady-state response y[n] to an input x[n] = u[n] + sin(Ï€n/2) u[n].

y[n] = {y[n – 1]+ w[n]

Step by Step Solution

3.34 Rating (154 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a Replacing wn in the smoother equation b If xn un then ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Questions!