Example 3.9: Throwing a die How many times must a die be thrown on the average to
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Example 3.9: Throwing a die How many times must a die be thrown on the average to produce the number 6? [Hint: The probability that in n trials the six appears once and no six n − 1 times is P(n) = (1/6)(5/6)n−1].
The answer is ˜n = 6.
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