Example 9.12: Debye frequency in a superconductor Considering the cubic metal lattice of a superconductor with neighbouring
Question:
Example 9.12: Debye frequency in a superconductor Considering the cubic metal lattice of a superconductor with neighbouring ion separation d at temperature T = 0, show that the Debye frequency is given by
ωD =
2√2
(meMaBd3)1/2 2√2
√meM√nd2
, (9.48)
where me is the mass of the electron, M that of an ion, aB the Bohr radius, and d naB, n an integer.
[Hint: Equate the oscillator potential of the ion to the energy of attraction between electron and ion, and express e2 in terms of aB, giving e2 2/med ].
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: