Let X have the Poisson distribution P( ), and consider the hypothesis H : = 0.

Let X have the Poisson distribution P(τ ), and consider the hypothesis H : τ = τ0. Then condition (4.6) reduces to C

2−1 x=C1+1

τx−1 0

(x − 1)! e

−τ0 +2 i=1

(1 − γi) τ Ci−1 0

(Ci − 1)! e

−τ0 = 1 − α, provided C1 > 1.