The data tally appears in Table 15.27. X2df -- (Ib - cl - 1)2/(b +

c) -

(4 - 1)2/8 = 1.125. From Table III, the critical value of X 2 for c~ - 0.05 with 1 df is 3.84. Because 1.125 < 3.84, you conclude that boys are not shown to have a greater accident rate. The actual p-value is 0.289.