=+2. Suppose the following argument is made for three-egg quiches rather than four-egg quiches: Let x 5 number of eggs that carry salmonella. Then p(0) 5 P(x 5 0) 5 (.75)3 5 .422 for three-egg quiches and p(0) 5 P(x 5 0) 5 (.75)4 5 .316 for four-egg quiches. What assumption must be made to justify these probability calculations? Do you think this is reasonable or not? Explain.