Figure P4.45 is the ac equivalent circuit of a common-gate amplifier. The transistor parameters are \(V_{T N}=0.4 \mathrm{~V}, k_{n}^{\prime}=100 \mu \mathrm{A} / \mathrm{V}^{2}\), and \(\lambda=0\). The quiescent drain current is \(I_{D Q}=0.25 \mathrm{~mA}\). Determine the transistor \(W / L\) ratio and the value of \(R_{D}\) such that the small-signal voltage gain is \(A_{v}=V_{o} / V_{i}=20\) and the input resistance is \(R_{i}=500 \Omega\).

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R T VB Figure P4.45 RD