The circuit parameters of the diff-amp shown in Figure 11.19 are (V^{+}=3 mathrm{~V}, V^{-}=-3 mathrm{~V}), and (I_{Q}=0.15

Question:

The circuit parameters of the diff-amp shown in Figure 11.19 are $V^{+}=3 \mathrm{~V}, V^{-}=-3 \mathrm{~V}$, and $I_{Q}=0.15 \mathrm{~mA}$. The transistor parameters are $K_{n}=0.2 \mathrm{~mA} / \mathrm{V}^{2}, V_{T N}=0.4 \mathrm{~V}$, and $\lambda=0$. Determine the value of $v_{d}=$ $v_{G 1}-v_{G 2}$ that produces

(a) $i_{D 1}=0.2 I_{Q}$,

(b) $i_{D 2}=0.8 I_{Q}$, and

(c) $i_{D 1}=I_{Q}$.

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