The circuit shown in Figure P9.47 can be used as a variable noninverting amplifier. The circuit uses

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The circuit shown in Figure P9.47 can be used as a variable noninverting amplifier. The circuit uses a $50 \mathrm{k} \Omega$ potentiometer in conjunction with an ideal op-amp.

(a) Derive the expression for the closed-loop voltage gain $v_{O} / v_{I}$ in terms of the potentiometer setting $x$.

(b) What is the range of closed-loop voltage gain?

(c) Is there a potential problem with this circuit? If so, what is the problem?

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Microelectronics Circuit Analysis And Design

ISBN: 9780071289474

4th Edition

Authors: Donald A. Neamen

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Question Posted: May 07, 2024 04:00 AM

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(a) Determine the closed-loop voltage gain $A_{v}=v_{O} / v_{I}$ for the ideal opamp circuit in Figure P9.48. (b) Determine $v_{O}$ for $v_{I}=0.25 \mathrm{~V}$. (c) Let \(R=30 \mathrm{k}...
(a) Derive the expression for the closed-loop voltage gain $A_{v}=v_{O} / v_{I}$ for the circuit shown in Figure P9.46. Assume an ideal op-amp. (b) Let $R_{4}=50 \mathrm{k} \Omega$ and \(R_{3}=25...
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The circuit shown in Figure P9.47 can be used as a variable noninverting amplifier. The circuit uses

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50 k2 potentiometer wwwwwww 1-x 0 + Figure P9.47

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Microelectronics Circuit Analysis And Design

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