Consider a circuit of two capacitors, (C_{1}) and (C_{2}), in series. Prove that the equivalent capacitance of

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Consider a circuit of two capacitors, \(C_{1}\) and \(C_{2}\), in series. Prove that the equivalent capacitance of the circuit is \(\frac{1}{C_{\mathrm{eq}}}=\frac{1}{C_{1}}+\frac{1}{C_{2}}\).

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