Consider the plane truss in example 1.5. Let (left{mathbf{F}^{(1)}ight}) be a unit force in the (x) direction
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Consider the plane truss in example 1.5. Let \(\left\{\mathbf{F}^{(1)}ight\}\) be a unit force in the \(x\) direction at node 1 and \(\left\{\mathbf{F}^{(2)}ight\}\) be a unit force in the y direction. Show that the displacements using the superposition principle, \(\{\mathbf{Q}\}=\alpha\left\{\mathbf{Q}^{(1)}ight\}+\beta\left\{\mathbf{Q}^{(2)}ight\}\), is the same as the actual displacements in Example 1.5, where \(\alpha=\beta=10,000 \sqrt{2}\).
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Related Book For
Introduction To Finite Element Analysis And Design
ISBN: 9781119078722
2nd Edition
Authors: Nam H. Kim, Bhavani V. Sankar, Ashok V. Kumar
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