Show that if the eigenvalues of (mathbf{A}) are (lambda_{1}, lambda_{2}, ldots, lambda_{n}), then the eigenvalues of (mathbf{A}-alpha

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Show that if the eigenvalues of \(\mathbf{A}\) are \(\lambda_{1}, \lambda_{2}, \ldots, \lambda_{n}\), then the eigenvalues of \(\mathbf{A}-\alpha \mathbf{I}\) are \(\lambda_{1}-\alpha, \lambda_{2}-\alpha, \ldots, \lambda_{n}-\alpha\).

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