Show that IOn = 4 mod 6 for all n ~ 1, and hence that if m
Question:
Show that IOn = 4 mod 6 for all n ~ 1, and hence that if m = n mod 6 then 10m = IOn mod 7.
From this determine the remainder when 1010 + 10(102
) + 10(103
) + ... + 10(1010
) is divided by 7.
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Related Book For 
Error Correcting Codes A Mathematical Introduction
ISBN: 978-0412786907
1st Edition
Authors: D J. Baylis
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