6.23 For the situation of Example 6.27: (a) Show that X = (X1, X2) is minimal sufficient...

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6.23 For the situation of Example 6.27:

(a) Show that X = (X1, X2) is minimal sufficient for the family (6.16) with restriction

(6.17).

(b) Establish (6.18), and hence that the minimal sufficient statistic of part

(a) is not complete.

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