His body is leaning back at 30.0^oto the vertical, but the coefficient of static friction between his feet and the ground is suddenly reduced to 0.50. What will happen?

(a) His entire body will accelerate forward;

(b) His feet will slip forward;

(c) His feet will slip backward;

(d) His feet will not slip.

In a study of the biomechanics of the tug-of-war, a 2.0-m-tall, 80.0-kg competitor in the middle of the line is considered to be a rigid body leaning back at an angle of 30.0^o to the vertical. The competitor is pulling on a rope that is held horizontal a distance of 1.5 m from his feet (as measured along the line of the body). At the moment shown in the figure, the man is stationary and the tension in the rope in front of him is T₁ = 1160 N. Since there is friction between the rope and his hands, the tension in the rope behind him, T₂, is not equal to T₁. His center of mass is halfway between his feet and the top of his head. The coefficient of static friction between his feet and the ground is 0.65.

Transcribed Image Text:

Side view. T2 1.5m 30°