Question: Suppose, for j = 1, 2,... ,n, that fj are real functions continuously differentiable on the interval (-1, 1). Prove that g(x) := f1(x1)

Suppose, for j = 1, 2,... ,n, that fj are real functions continuously differentiable on the interval (-1, 1). Prove that
g(x) := f1(x1) ∙ ∙ ∙ fn(xn)
is differentiable on the cube (-1, 1) × (-1, 1) × ∙ ∙ ∙ × (-1, 1).

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