Question: Suppose we want to add an extra operation, deunion, which undoes the last union operation that has not been already undone. a. Show that if

Suppose we want to add an extra operation, deunion, which undoes the last union operation that has not been already undone.

a. Show that if we do union-by-height and finds without path compression, then deunion is easy and a sequence of M union, find, and deunion operations takes O(MlogN) time.

b. Why does path compression make deunion hard?

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