The copper(I) ion forms a complex ion with CN- according to the following equation: Cu+(aq) + 3CN-(aq)
Question:
Cu+(aq) + 3CN-(aq) ⇌ Cu(CN)32-(aq) Kf = 1.0 × 1011
a. Calculate the solubility of CuBr(s) (Ksp = 1.0 × 10-5) in 1.0 L of 1.0 M NaCN.
b. Calculate the concentration of Br- at equilibrium.
c. Calculate the concentration of CN- at equilibrium.
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a CuBrs Cu Br K sp 10 10 5 Cu 3 CN CuCN 3 2 K f 10 10 11 CuBrs 3 CN CuCN 3 2 Br K 10 10 6 Because K ...View the full answer
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