Question: The figure shows the Sun located at the origin and Earth at the point (1, 0). (The unit here is the distance between the centers
The figure shows the Sun located at the origin and Earth at the point (1, 0).
(The unit here is the distance between the centers of Earth and the Sun, called an astronomical unit: 1 AU ≈ 1.496 X 108 km.) There are five locations L1, L2, L3, L4, and in this plane of rotation of Earth about the Sun where a satellite remains motionless with respect to Earth because the forces acting on the satellite (including the gravitational attractions of Earth and the Sun) balance each other. These locations are called liberation points. (A solar research satellite has been placed at one of these liberation points.)
If m1 is the mass of the Sun, m2 is the mass of Earth, and r = m2 / (m1 + m2), it turns out that the -coordinate of L1 is the unique root of the fifth-degree equation and the x-coordinate of L2 is the root of the equation p(x) 2rx2 = 0.
Using the value r ≈ 3.04046 x 10-6, find the locations of the liberation points
(a) L1 and
(b) L2.
p(x) = x* - (2 + r)x* + (1 + 2r)x (1 r)x? + 2(1 r)x + r- 1 = 0 y. L. Earth Sun L5 L3 L,
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a px x 2rx 12rx 1rx 21rxr1 px 5x 42rx 312rx 21rx 21r So we use In1 In x 2 r 1 2rx 1rx 21 rn r1 5x4... View full answer
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