The fill volume of cans filled by a certain machine is normally distributed with mean 12.05 oz
Question:
a. What proportion of cans contain less than 12 oz?
b. The process mean can be adjusted through calibration. To what value should the mean be set so that 99% of the cans will contain 12 oz or more?
c. If the process mean remains at 12.05 oz, what must the standard deviation be so that 99% of the cans will contain 12 oz or more?
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a The z score of 12 is 12 12 05 0 03 1 67 The area to the left ...View the full answer
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