The period of a simple pendulum of length L feet is given by T = 2 L/g

The period of a simple pendulum of length L feet is given by T = 2π √L/g seconds. We assume that g, the acceleration due to gravity on (or very near) the surface of the earth, is 32 feet per second per second. If the pendulum is that of a clock that keeps good time when L = 4 feet, how much time will the clock gain in 24 hours if the length of the pendulum is decreased to 3.97 feet?