The production of 1,3-butadiene can be carried out by the dehydrogenation of n- butane:
C4H 10(g) → CH2 : CHCH : CH2(g) + 2H2(g)
Side reactions are suppressed by the introduction of steam. If equilibrium is attained at 925 K and 1 bar and if the reactor product contains 12-mol-% 1, 3-butadiene, find:
(a) The mole fractions of the other species in the product gas.
(b) The mole fraction of steam required in the feed.