The second reaction in the proton proton chain (see Fig 43 17) produces a 32He nucleus A 32He nucleus produced in this way can combine with a 42He nucleus 32He 42He 74Be Calculate the energy liberated in this process (This is shared between the energy of the photon and the recoil kinetic energy of the beryllium nucleus ) The mass of a 42 He atom is 7 016929 u

Question: The second reaction in the proton-proton chain (see Fig. 43.17) produces a 32He nucleus. A 32He nucleus produced in this way can combine with a

The second reaction in the proton-proton chain (see Fig. 43.17) produces a 32He nucleus. A 32He nucleus produced in this way can combine with a 42He nucleus: 32He + 42He → 74Be+ γ Calculate the energy liberated in this process. (This is shared between the energy of the photon and the recoil kinetic energy of the beryllium nucleus.) The mass of a 42 He atom is 7.016929 u

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