The solution to Exercise 1 of Sec. 3.9 is the p.d.f. of X1 + X2 in Example

Question:

The solution to Exercise 1 of Sec. 3.9 is the p.d.f. of X1 + X2 in Example 6.1.2. Find the p.d.f. of 2 = (X1 + X2)/2. Compare the probabilities that X2 and X1 are close to 0.5. In particular, compute Pr(|X2 − 0.5| < 0.1) and Pr(|X1 − 0.5| < 0.1). What feature of the p.d.f. of X2 makes it clear that the is more concentrated near the mean? Distribution
The word "distribution" has several meanings in the financial world, most of them pertaining to the payment of assets from a fund, account, or individual security to an investor or beneficiary. Retirement account distributions are among the most...