The theoretical limit for extracting solute S from phase 1 (volume V₁) into phase 2 (volume V₂) is attained by dividing V₂ into an infinite number of infinitesimally small portions and conducting an infinite number of extractions. With a partition coefficient K = [S]₂/[S]₁, the limiting fraction of solute remaining in phase 1 is 2 qlimit = e^{- (V2/V1)K}. Let k = V₁ = V₂ = 50 mL and let K = 2. Let volume V2 be divided into n equal portions to conduct n extractions. Find the fraction of S extracted into phase 2 for n = 1, 2, 10 extractions. How many portions are required to attain 95% of the theoretical limit?