The values of E b /N 0 required to realize an average probability or symbol error P
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The values of Eb/N0 required to realize an average probability or symbol error Pa = 10-4 using coherent binary PSK and coherent FSK (conventional) systems are equal to 7.2 and 13.5, respectively. Using the approximation determine the separation in the values of Eb/N0 for Pe = 10?4 using
(a) Coherent binary PSK and DPSK.
(b) Coherent binary PSK and QPSK.
(c) Coherent binary FSK (conventional) and non-coherent binary FSK.
(d) Coherent binary FSK (conventional) and coherent MSK.
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a For a coherent PSK system the average probability of error is P er foEN e 12 expEN CENO For a DPSK ...View the full answer
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