Question: The values of E b /N 0 required to realize an average probability or symbol error P a = 10 -4 using coherent binary PSK

The values of E_b/N₀ required to realize an average probability or symbol error P_a = 10^-4 using coherent binary PSK and coherent FSK (conventional) systems are equal to 7.2 and 13.5, respectively. Using the approximation determine the separation in the values of E_b/N₀ for P_e = 10^?4 using

(a) Coherent binary PSK and DPSK.

(b) Coherent binary PSK and QPSK.

(d) Coherent binary FSK (conventional) and coherent MSK.

exp(- ?) erfclu) V

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a For a coherent PSK system the average probability of error is P er foEN e 12 expEN CENO For a DPSK ... View full answer

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