Use the Newton forward-difference formula to construct interpolating polynomials of degree one, two, and three for the
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a. f (0.43) if f (0) = 1, f (0.25) = 1.64872, f (0.5) = 2.71828, f (0.75) = 4.48169
b. f (0.18) if f (0.1) = −0.29004986, f (0.2) = −0.56079734, f (0.3) = −0.81401972, f (0.4) = −1.0526302
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In the following equations we have s 1h x x 0 a P 1 s 10 06487200000s P 1 ...View the full answer
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