We saw in Section 8.3 that addition of HBr to a terminal alkyne leads to the Markovnikov
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We saw in Section 8.3 that addition of HBr to a terminal alkyne leads to the Markovnikov addition product, with the Br bonding to the more highly substituted carbon. How could you use 13C NMR to identify the product of the addition of 1 equivalent of HBr to 1-hexyne?
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CH3CHCHCHCCH Br CH3CHCHCHCCH 2Bromo1hexene or CH3CHCHCHCHCHBr 1Brom...View the full answer
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