(a) Compute the current I = dQ/dt from the solution of Equation 31-47b given in Problem 91, and show that

Where I₀ = ω’Q₀.

(b) Show that this can be written

Where tan δ = R/2Lω’. When R/2Lω’ is small, cos δ ≈ 1, and I ≈ I₀ sin (ω’t + δ)e^-Rt/2L

Transcribed Image Text:

d'Q di2 31-47b 31-47b dt 0= 3pY R I = -lo| sin o't + 2 Lo' cos o't le-R/21.