A solution containing 50.0 mL of 0.100 M EDTA buffered to pH 10.00 was titrated with 50.0
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A solution containing 50.0 mL of 0.100 M EDTA buffered to pH 10.00 was titrated with 50.0 mL of 0.020 0 M Hg(ClO4)2 in the cell shown in Exercise 14-B:
S.C.E. 7 titration solution | Hg(l)
From the cell voltage E = - 0.027 V, find the formation constant of Hg(EDTA)2-.
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The reaction in the right halfcell is Hg 2 2e Hgl E E E 00...View the full answer
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