Absorption with chernical reaction 

(a) Rework the problem discussed in the text in S18.4, but take z = 0 to be the bottom of the beaker and z = L at the gas-liquid interface. 

(b) In solving Eq. 18.4-7, we took the solution to be of the sum of two hyperbolic functions. 

Try solving the problem by using the equally valid solution Г = C₁ exp (bζ + C₂ exp (– bζ) 

(c) In what way do the results in Eqs. 18.4-10 and 12 simplify for very large L for very small L? Interpret the results physically.