Consider the variation of Gauss-Jordan elimination in which zeros are introduced above and below a leading 1 as soon as it is obtained, and let
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Consider the variation of Gauss-Jordan elimination in which zeros are introduced above and below a leading 1 as soon as it is obtained, and let A be an invertible n × n matrix. Show that to solve a linear system Ax = b using this version of Gauss-Jordan elimination requires
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n3/2 + n2/2 multiplications and n3/2 - n/2 additions
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To solve a linear system whose coefficient matrix is an invertible n n matrix A we form the n n 1 ma... View full answer

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