Question: Figure 4-34a (P4.52 (a)) depicts a capacitor consisting of two parallel, conducting plates separated by a distance d. The space between the plates contains two

Figure 4-34a (P4.52 (a)) depicts a capacitor consisting of two parallel, conducting plates separated by a distance d. The space between the plates contains two adjacent dielectrics,


A1 A2 E2 C2 (b) E141 C1 = (4.133) E242 C2 = (4.134) One with permittivity 1 and surface area A1 and another with 2 and A2 the objective of this problem is to show that the capacitance C of the configuration shown in Fig. 4-34a (P4.52(a)) is equivalent to two capacitances in parallel, as illustrated in Fig. 4-34b (P4.52(b)), with C = C1. C2, where To this end, you are asked to proceed as follows:
(a) Find the electric fields E1 and E2 in the two dielectric layers.
(b) Calculate the energy stored in each section and use the result to calculate C1 and C2.
(c) Use the total energy stored in the capacitor to obtain an expression for C. Show that Eq. (4.132) is indeed a valid result.

A1 A2 E2 C2 (b) E141 C1 = (4.133) E242 C2 = (4.134)

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