Find the error in the following proof that 0 = 1, In (1/t) dt, set u

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Find the error in the following "proof" that 0 = 1, In ∫ (1/t) dt, set u = 1/t and dv = dt. Then du = -t-2 dt and uv = 1. Integration by parts gives
∫ (1/t)dt = 1 - ∫ (-1/t)dt or 0 = 1
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Calculus

ISBN: 978-0131429246

9th edition

Authors: Dale Varberg, Edwin J. Purcell, Steven E. Rigdon

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