Kuttas third-order method is define by yn + 1 = yn + 1/6 (k1 + 4k2 +

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Kutta’s third-order method is define by yn + 1 = yn + 1/6 (k1 + 4k2 + k3*) with k1 and k2 as in RK Table 21.4 and k3* = hf (xn+1, yn – k1 + 2k2). Apply this method to (4) in example 1. Choose h = 0.2 and d0 5 steps. Compare with Table 21.6

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Advanced Engineering Mathematics

ISBN: 978-0471488859

9th Edition

Authors: ERWIN KREYSZIG

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Question Posted: Nov 07, 2010 06:01 AM

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Kuttas third-order method is define by yn + 1 = yn + 1/6 (k1 + 4k2 +

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From y x y and the given formula we get with h 02 k 02x yn k 02xn 01 yn ...View the full answer

Advanced Engineering Mathematics

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