Question: Kuttas third-order method is define by yn + 1 = yn + 1/6 (k1 + 4k2 + k3*) with k1 and k2 as in RK

Kutta’s third-order method is define by yn + 1 = yn + 1/6 (k1 + 4k2 + k3*) with k1 and k2 as in RK Table 21.4 and k3* = hf (xn+1, yn – k1 + 2k2). Apply this method to (4) in example 1. Choose h = 0.2 and d0 5 steps. Compare with Table 21.6

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