Question: A liquidgas fuel mixture consists of 90 percent octane (C8H18), and 10 percent alcohol (C2H5OH), by moles. This fuel is burned with 200 percent theoretical
A liquid–gas fuel mixture consists of 90 percent octane (C8H18), and 10 percent alcohol (C2H5OH), by moles. This fuel is burned with 200 percent theoretical dry air. Write the balanced reaction equation for complete combustion of this fuel mixture. Determine (a) the theoretical air–fuel ratio for this reaction; (b) the product–fuel ratio for this reaction;
(c) The air-flow rate for a fuel mixture flow rate of 5 kg/s; and
(d) The lower heating value of the fuel mixture with 200 percent theoretical air at 25°C.
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A liquid gas fuel mixture consisting of 90 octane CH1s and 10 alcohol CHOH by moles is burned with 200 theoretical dry air The balanced reaction equat... View full answer
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