Reconsider the system defect situation described in Exercise 26 (Section 2.2). In Exercise 26 A certain system
Question:
In Exercise 26
A certain system can experience three different types of defects. Let Ai (i = 1,2,3) denote the event that the system has a defect of type i. Suppose that
P(A1) = .12 P(A2) = .07 P(A3) = .05
P(A1 ⋃ A2) = .13 P(A1 ⋃ A3) = .14
P(A2 ⋃ A3) = .10 P(A1 ⋂ A2 ⋂ A3) = .01
a. Given that the system has a type 1 defect, what is the probability that it has a type 2 defect?
b. Given that the system has a type 1 defect, what is the probability that it has all three types of defects?
c. Given that the system has at least one type of defect, what is the probability that it has exactly one type of defect?
d. Given that the system has both of the first two types of defects, what is the probability that it does not have the third type of defect?
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a 0612 50 The numerator comes from Exercise 26 b 0112 0833 The numerator ...View the full answer
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Related Book For 
Probability And Statistics For Engineering And The Sciences
ISBN: 9781305251809
9th Edition
Authors: Jay L. Devore
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