Saturated steam at 1.35 atm condenses on the outside of a 2.6 m length of copper tubing
Question:
Saturated steam at 1.35 atm condenses on the outside of a 2.6 m length of copper tubing heating 5m kg/hr of water flowing in the tube. The water temperatures, measured at 10 equally spaced stations along the tube length are
Calculate (a) average overall heat transfer coefficient Uo based on the outside tube area; (b) average water-side heat transfer coefficient hw (assume steamside coefficient at hs = 11,000 W/(m2 K)), (c) local overall coefficient Ux based on the outside tube area for each of the 10 sections between temperature stations, and (d) local waterside coefficients hwx for each of the 10 sections. Plot all items vs. tube length. Tube dimensions: ID = 2 cm, OD = 2.5 c. Temperature station 1 is at tube entrance and station 11 is at tube exit.GIVENSaturated steam condensing on copper tubing with water flowing withinSteam pressure = 1.35 atm = 136,755 N/m2Tube length (L) = 2.6 mWater flow rate (mw) = 5 kg/h = 0.00139 kg/sWater temperatures given above as a function of distance along pipeTube diametersDi = 2 cm = 0.02 mDo = 2.5 cm = 0.025 mASSUMPTIONSThe steam-side heat transfer coefficient hs = 11,000 W/(m2 K)No scaling resistanceVariation of the specific heat of water isnegligible
Step by Step Answer:
Principles of heat transfer
ISBN: 978-0495667704
7th Edition
Authors: Frank Kreith, Raj M. Manglik, Mark S. Bohn