Show that a. E(X2) [E(X)2] b. cov (X,Y) = E[(X - X)(Y - Y)] = E(XY)
Question:
a. E(X2) ≥ [E(X)2]
b. cov (X,Y) = E[(X - µX)(Y - µY)]
= E(XY) - µXµY
where µX = E(X) and µY = E(Y).
How would you express these formulas verbally?
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a var X EX 2 EX 2 0 since the variance is always pos...View the full answer
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