Question: Show that if h[n] is an N-point FIR filter such that h[n] = h[N 1 n] and H(z 0 ) = 0, then

Show that if h[n] is an N-point FIR filter such that h[n] = h[N – 1 – n] and H(z0) = 0, then H(1/z0) = 0. This shows that even symmetric linear-phase FIR filters have zeros that are reciprocal images. (If h[n] is real, the zeros also will be real or will occur in complex conjugates.)

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