Let K be an algebraically closed field. Show that every isomorphism of K onto a subfield
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Let K be an algebraically closed field. Show that every isomorphism σ of K onto a subfield of itself such that K is algebraic over σ[K] is an automorphism of K, that is, is an onto map.
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Now K K is an isomorphism so 1 K K is an isomorphism Because K is algebraically closed and is algebraic ...View the full answer
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