Let K be an algebraically closed field Show that every isomorphism of K onto a subfield of itself such that K is algebraic over K is an automorphism of K, that is, is an onto map ...

Now K K is an isomorphism so 1 K K is an isomorphism Because K is algebraically closed and is algebraic ...

Let K be an algebraically closed field. Show that every isomorphism of K onto a subfield

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Let K be an algebraically closed field. Show that every isomorphism σ of K onto a subfield of itself such that K is algebraic over σ[K] is an automorphism of K, that is, is an onto map.

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A First Course In Abstract Algebra

ISBN: 9780201763904

7th Edition

Authors: John Fraleigh

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Question Posted: Jan 16, 2023 02:51 AM

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Let K be an algebraically closed field. Show that every isomorphism of K onto a subfield

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Now K K is an isomorphism so 1 K K is an isomorphism Because K is algebraically closed and is algebraic ...View the full answer

A First Course In Abstract Algebra

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