Use Problem 50 to show that the steady-state current in an LRC-series circuit when L = ½ h, R = 20 Ω, C = 0.001 f, and E(t) = 100 sin 60t V, is given by ip(t) = 4.160 sin(60t - 0.588).

Problem 50

Show that the amplitude of the steady-state current in the LRC-series circuit in Example 10 is given by E₀/Z, where Z is the impedance of the circuit.