The equation describes the motion of an object thrown upward into the air. In the equation, g is the acceleration due to gravity (9.8m/s²), t is the time elapsed since the object was thrown upward, ν₀ is the initial speed of the object, h₀ is the initial height from which the object was thrown, and h is the height of the object above the ground t seconds after the object was thrown.

How many seconds will it take the object to reach its maximum height? (The function has a maximum point at t =  -b/2a).

Transcribed Image Text:

h = 1 2 60 + vot + ho