Find the y intercepts and the x intercepts and use them as the two points needed to graph the following linear equations:

(a) y = 5x + 10 y intercept: (0, 10), x intercept: (−2, 0). See Fig. 2-13.

(g) y = 2x y intercept: (0, 0), x intercept (0, 0). When the x and y intercepts coincide, as occurs when the graph passes through the origin, a second distinct point must be found. Letting x = 1 for ease of computation, y = 2(1) = 2. The graph can now be constructed from the points (0, 0) and (1, 2).
See Fig. 2-19.

(h) y = 3 y intercept: (0, 3); the x intercept does not exist because y cannot be set equal to zero without involving a contradiction. Since y = 3 independently of x, y will equal 3 for any value of x. The graph is simply a horizontal line 3 units above the x axis. Paralleling the x axis, it never crosses it. See Fig. 2-20.

Transcribed Image Text:

y y=5x+10 10 8 e 4 21 - x -3/2-1 1 2 345 Fig. 2-13 y intercept: (0, 9), x intercept: (3, 0). See Fig. 2-14. (b) y=-3x+9