How much wine with an 18% alcohol content must be mixed with 6000 gallons of wine with

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How much wine with an 18% alcohol content must be mixed with 6000 gallons of wine with a 12%

alcohol content to obtain wine with a 16% alcohol content?

Letting x = the amount of wine with 18% alcohol to be mixed and y = the alcohol content of the mixture, then image text in transcribed

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Schaum S Outline Of Mathematical Methods For Business Economics And Finance

ISBN: 978-1264266876

2nd Edition

Authors: Luis Moises Pena Levano

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Question Posted: Sep 20, 2024 06:02 AM

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How much wine with an 18% alcohol content must be mixed with 6000 gallons of wine with a 12% alcohol content to obtain wine with a 16% alcohol content? Letting x = the amount of wine with 18% alcohol...
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How much wine with an 18% alcohol content must be mixed with 6000 gallons of wine with

Question:

y=.18x+.12(6000) Then substituting the desired mixture of (6000+x) gallons with 16% alcohol for y, .16(6000+x) = .18x+.12(6000) 960.16x18x + 720 -0.02x=-240 x=12,000 gallons

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Schaum S Outline Of Mathematical Methods For Business Economics And Finance

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