Show that the surface area of the cone z = kx + y, k > 0, over

Show that the surface area of the cone z = k√x² + y², k > 0, over the circular region x² + y² ≤ r² in the xy-plane is πr²√k² + 1 (see figure).

Transcribed Image Text:

N z=k√√x² + y² R: x² + y² ≤r² y